Generating Uri with Query and Fragment

mimmi20 · January 9, 2026, 6:03pm

Actually it is not possible to generate an Uri for a route with Query parameters or a fragment.

Does anyone know why this behavior was enforced?

froschdesign · January 9, 2026, 6:28pm

The problem could be:

src/LaminasRouter.php

99be8034f


      
          $options = array_merge($options, [
              'name'             => $name,
              'only_return_path' => true,
          ]);

github.com/laminas/laminas-router

src/Http/TreeRouteStack.php

5e5554e9d


      
          if (isset($options['only_return_path']) && $options['only_return_path']) {
              return $this->baseUrl . $route->assemble(array_merge($this->defaultParams, $params), $options);
          }
          
          if (! isset($options['uri']) || ! $options['uri'] instanceof HttpUri) {
              $uri = new HttpUri();
          
              if (isset($options['force_canonical']) && $options['force_canonical']) {
                  if ($this->requestUri === null) {
                      throw new Exception\RuntimeException('Request URI has not been set');
                  }
          
                  $uri->setScheme($this->requestUri->getScheme())
                      ->setHost($this->requestUri->getHost())
                      ->setPort($this->requestUri->getPort());
              }
          
              $options['uri'] = $uri;
          } else {
              $uri = $options['uri'];

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Generating Uri with Query and Fragment

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